Algebra - Simple Equations - Previous Year CAT/MBA Questions
The best way to prepare for Algebra - Simple Equations is by going through the previous year Algebra - Simple Equations CAT questions.
Here we bring you all previous year Algebra - Simple Equations CAT questions along with detailed solutions.
Click here for previous year questions of other topics.
It would be best if you clear your concepts before you practice previous year Algebra - Simple Equations CAT questions.
Use the following information:
Eighty five children went to an amusement park where they could ride on the merry – go round, roller coaster, and Ferris wheel. It was known that 20 of them took all three rides, and 55 of them took at least two of the three rides. Each ride cost Re.1, and the total receipt of the amusement park was Rs.145.
76. CAT 1993 QA | Algebra - Simple Equations CAT Question
How many children did not try any of the rides?
- (a)
5
- (b)
10
- (c)
15
- (d)
20
Answer: Option
C
Text Explanation :
Let x, y and z be the number of children who took 1 rides, 2 rides and 3 rides respectively.
Since z = 20 and y + z = 55, y = 35.
Then, total number of rides = x + 2y + 3z = 145
⇒ x + 2 × 35 + 3 × 20 = 145
⇒ x = 15
Number of children, who did not try any of the rides
= 85 – (x + y + z)
= 85 – (15 + 35 + 20) = 15
Hence, option (c).
77. CAT 1993 QA | Algebra - Simple Equations CAT Question
How many children took exactly one ride?
- (a)
5
- (b)
10
- (c)
15
- (d)
20
Answer: Option
C
Text Explanation :
Consider the solution to previous question of this set.
Number of children taking exactly one ride = 15.
Hence, option (c).
78. CAT 1993 QA | Algebra - Simple Equations CAT Question
John bought five mangoes and ten oranges together for forty rupees. Subsequently, he returned one mango and got two oranges in exchange. The price of an orange would be
- (a)
Rs. 1
- (b)
Rs. 2
- (c)
Rs. 3
- (d)
Rs. 4
Answer: Option
B
Text Explanation :
The price of 1 mango is equal to the price of 2 oranges.
Hence, 5 mangoes will be equivalent to 10 oranges.
So, 20 oranges cost Rs.40, therefore one orange will cost Rs.2.
Hence, option (b).
79. CAT 1991 QA | Algebra - Simple Equations CAT Question
What is the value of k for which the following system of equations has no solution:
2x – 8y = 3 and kx +4y = 10
- (a)
-2
- (b)
1
- (c)
-1
- (d)
2
Answer: Option
C
Text Explanation :
For two lines a1x + b1y = c1 and a2x + b2y = c2 to be parallel, the condition is
= ≠
For no solution, lines must be parallel and not over lapping
⇒
∴ k = − 1.
Hence, option (c).
80. CAT 1991 QA | Algebra - Simple Equations CAT Question
Iqbal dealt some cards to Mushtaq and himself from a full pack of playing cards and laid the rest aside. Iqbal then said to Mushtaq. “If you give me a certain number of your cards, I will have four times as many cards as you will have. If I give you the same number of cards, I will have thrice as many cards as you will have “. Of the given choices, which could represent the number of cards with Iqbal?
- (a)
9
- (b)
31
- (c)
12
- (d)
35
Answer: Option
B
Text Explanation :
Let Mushtaq has M cards while Iqbal has got I cards with him.
Let number of cards exchanged be x.
Case 1: I + x = 4(M – x) ... (i)
Case 2: I – x = 3(M + x) ... (ii)
From (i) and (ii)
I = 31x
Since I + M has to be less than or equal to 52, the only possible value for I could be 31.
Hence, option (b).
81. CAT 1991 QA | Algebra - Simple Equations CAT Question
Three times the first of three consecutive odd integers is 3 more than twice the third. What is the third integer?
- (a)
15
- (b)
9
- (c)
11
- (d)
5
Answer: Option
A
Text Explanation :
Let the 3 odd numbers be (x – 2), x and (x + 2).
It is given that 3(x – 2) = 3 + 2(x + 2).
Hence x = 13.
So the third integer is (x + 2) = 15.
Hence, option (a).
82. CAT 1991 QA | Algebra - Simple Equations CAT Question
Gopal went to a fruit market with certain amount of money. With this money he can buy either 50 oranges or 40 mangoes. He retains 10% of the money for taxi fare. If he buys 20 mangoes, then the number of oranges he can buy is
- (a)
25
- (b)
20
- (c)
18
- (d)
6
Answer: Option
B
Text Explanation :
Let the amount with Gopal be Rs. 400.
Therefore price of an orange is then Rs. 8 and that of a mango is Rs.10.
If he keeps 10% of the money for taxi fare, he is left with Rs.360.
Now if he buys 20 mangoes, then he spends on mangoes Rs. 200.
Now he is left with Rs.160, in which he can buy = 160/8 = 20 oranges.
Hence, option (b).
Solution
Discuss
Report