LR - Selection & Distribution - Previous Year CAT/MBA Questions
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77. CAT 2018 LRDI Slot 1 | LR - Selection & Distribution CAT Question
Which of the following CANNOT be determined uniquely based on the given information?
- (a)
The size of the teaching committee
- (b)
The size of the research committee
- (c)
The total number of educationalists in the three committees
- (d)
The total number of bureaucrats in the three committees
Answer: Option
A
Text Explanation :
Statements 2, 3 and 4 can be uniquely determined. The size of teaching committee can be 5 or 6. Thus, statement 1 cannot be uniquely determined.
Hence, option (a).
Answer the following question based on the information given below.
Adriana, Bandita, Chitra, and Daisy are four female students, and Amit, Barun, Chetan, and Deb are four male students. Each of them studies in one of three institutes - X, Y, and Z. Each student majors in one subject among Marketing, Operations, and Finance, and minors in a different one among these three subjects. The following facts are known about the eight students:
- Three students are from X, three are from Y, and the remaining two students, both female, are from Z.
- Both the male students from Y minor in Finance, while the female student from Y majors in Operations.
- Only one male student majors in Operations, while three female students minor in Marketing.
- One female and two male students major in Finance.
- Adriana and Deb are from the same institute. Daisy and Amit are from the same institute.
- Barun is from Y and majors in Operations. Chetan is from X and majors in Finance.
- Daisy minors in Operations.
78. CAT 2018 LRDI Slot 1 | LR - Selection & Distribution CAT Question
Who are the students from the institute Z?
- (a)
Adriana and Bandita
- (b)
Bandita and Chitra
- (c)
Chitra and Daisy
- (d)
Adriana and Daisy
Answer: Option
B
Text Explanation :
From (1), the institute Z has two female students. From (5), Adriana and Daisy are not the female students from the institute Z.
Thus, Bandita and Chitra are the students from the institute Z.
Hence, option (b).
79. CAT 2018 LRDI Slot 1 | LR - Selection & Distribution CAT Question
Which subject does Deb minor in?
Answer: Option
A
Text Explanation :
From (2), Y has two male and one female student. Hence, from (1), X has two male and one female student.
From (2), female student from Y majors in Operations. Daisy minors in Operations. So Daisy (and also Amit) is not from Y.
Therefore, from (5), Adriana and Deb are from the same institute and that has to be institute Y. From (2), both male students from Y minor in Finance.
Hence, Deb minors in Finance.
Hence, option (a).
80. CAT 2018 LRDI Slot 1 | LR - Selection & Distribution CAT Question
Which subject does Amit major in?
Answer: Option
A
Text Explanation :
From (2), Y has two male and one female student. Hence, from (1), X has two male and one female student.
From (2), both male students from Y minor in Finance and female student from Y majors in Operations.
Daisy minors in Operations. So Daisy (and also Amit) is not from Y.
Therefore, Amit and Daisy are from institute X. From (4), one female students and two male students major in Finance.
We know that a subject in which a student majors is difference from a subject in which he/she minors.
Hence, the two male students those majors in Finance must be from institute X.
So, Amit majors in Finance.
Hence, option (a).
81. CAT 2018 LRDI Slot 1 | LR - Selection & Distribution CAT Question
If Chitra majors in Finance, which subject does Bandita major in?
Answer: Option
C
Text Explanation :
From (2), Y has two male and one female student. Hence, from (1), X has two male and one female student. From (2), female student from Y majors in Operations. Daisy minors in Operations. So Daisy (and also Amit) is not from Y.
From (6),
X: Amit, Chetan and Daisy
Y: Barun, Deb and Adriana
Z: Bandita and Chitra
From (3) and (7), Daisy minors in Operations and remaining three girls minors in Marketing.
From (4), the one female student majors in Finance is Chitra. Hence, Bandita majors in Operations.
Hence, option (c).
Answer the following question based on the information given below.
Fuel contamination levels at each of 20 petrol pumps P1, P2, …, P20 were recorded as either high, medium, or low.
- Contamination levels at three pumps among P1 – P5 were recorded as high.
- P6 was the only pump among P1 – P10 where the contamination level was recorded as low.
- P7 and P8 were the only two consecutively numbered pumps where the same levels of contamination were recorded.
- High contamination levels were not recorded at any of the pumps P16 – P20.
- The number of pumps where high contamination levels were recorded was twice the number of pumps where low contamination levels were recorded.
82. CAT 2018 LRDI Slot 1 | LR - Selection & Distribution CAT Question
Which of the following MUST be true?
- (a)
The contamination level at P10 was recorded as high.
- (b)
The contamination level at P12 was recorded as high.
- (c)
The contamination level at P13 was recorded as low.
- (d)
The contamination level at P20 was recorded as medium.
Answer: Option
A
Text Explanation :
From (5), the number of pumps where high contamination levels were recorded is even.
From (1) and (2), high contamination levels recorded at 3 petrol pumps among P1 - P6 i.e., P1, P3 and P5 recorded high levels of contamination.
Therefore, using (4) it can be concluded that high contamination levels could have been recorded at pumps P7 – P15. From (3), the maximum number of pumps where the high contamination levels were recorded must be 5. So this number could be 1, 3 or 5 among P7 – P15.
So, we have the following cases.
From (3), the number of pumps with the same levels of contamination cannot be more than 11.
For 11 pumps with same levels of contamination, P1 and P20 should have the same level of contamination, which is not the case as P1 recorded high levels of contamination while P20 recorded either low or medium levels of contamination. Thus, cases (i) and (ii) are not valid.
Considering case iii we have the following cases:
Refer case1 given in the last table.
Statements [1] and [3] are false.
Refer case 6 given in the last table.
Statement [4] is false.
It can be seen that the contamination level at P10 was recorded as high in each case.
Hence, option (a).
83. CAT 2018 LRDI Slot 1 | LR - Selection & Distribution CAT Question
What best can be said about the number of pumps at which the contamination levels were recorded as medium?
- (a)
More than 4
- (b)
At most 9
- (c)
Exactly 8
- (d)
At least 8
Answer: Option
C
Text Explanation :
At exactly 8 petrol pumps, the contamination levels were recorded as medium.
Hence, option (c).
84. CAT 2018 LRDI Slot 1 | LR - Selection & Distribution CAT Question
If the contamination level at P11 was recorded as low, then which of the following MUST be true?
- (a)
The contamination level at P18 was recorded as low.
- (b)
The contamination level at P12 was recorded as high.
- (c)
The contamination level at P14 was recorded as medium.
- (d)
The contamination level at P15 was recorded as medium.
Answer: Option
C
Text Explanation :
If the contamination level at P11 was recorded as low, then case 1 is the only valid case. Statement of option [3] is the only true statement.
Hence, option (c).
85. CAT 2018 LRDI Slot 1 | LR - Selection & Distribution CAT Question
If contamination level at P15 was recorded as medium, then which of the following MUST be FALSE?
- (a)
Contamination levels at P11 and P16 were recorded as the same.
- (b)
Contamination levels at P10 and P14 were recorded as the same.
- (c)
Contamination level at P14 was recorded to be higher than that at P15.
- (d)
Contamination levels at P13 and P17 were recorded as the same.
Answer: Option
A
Text Explanation :
Answer the following question based on the information given below.
Seven candidates, Akil, Balaram, Chitra, Divya, Erina, Fatima, and Ganeshan, were invited to interview for a position. Candidates were required to reach the venue before 8 am. Immediately upon arrival, they were sent to one of three interview rooms: 101, 102, and 103. The following venue log shows the arrival times for these candidates. Some of the names have not been recorded in the log and have been marked as ‘?’.
Additionally here are some statements from the candidates: Balaram: I was the third person to enter Room 101. Chitra: I was the last person to enter the room I was allotted to. Erina: I was the only person in the room I was allotted to. Fatima: Three people including Akil were already in the ro om that I was allotted to when entered it. Ganeshan : I was one among the two candidates allotted to Room 102.
86. CAT 2018 LRDI Slot 2 | LR - Selection & Distribution CAT Question
What best can be said about the room to which Divya was allotted?
Answer: Option
A
Text Explanation :
From Ganeshan’s statement, there were two candidates in room 102. From Erina’s statement, she was the only candidate in her room.
However, from Balram’s statement, there were at least three candidates in the room 101. Therefore, there were 4 candidates in room 101, 2 candidates in room 102 and 1 candidate in room 103.
Using the given statements, we can generate the following:
Now all the questions can be answered.
Hence, option (a).
87. CAT 2018 LRDI Slot 2 | LR - Selection & Distribution CAT Question
Who else was in Room 102 when Ganeshan entered?
- (a)
Akil
- (b)
Divya
- (c)
Chitra
- (d)
No one
Answer: Option
D
Text Explanation :
From Ganeshan’s statement, there were two candidates in room 102. From Erina’s statement, she was the only candidate in her room.
However, from Balram’s statement, there were at least three candidates in the room 101. Therefore, there were 4 candidates in room 101, 2 candidates in room 102 and 1 candidate in room 103.
Using the given statements, we can generate the following:
Noone was there in the room when Ganeshan entered.
Hence, option (c).
88. CAT 2018 LRDI Slot 2 | LR - Selection & Distribution CAT Question
When did Erina reach the venue?
- (a)
7:10 am
- (b)
7:15 am
- (c)
7:25 am
- (d)
7:45 am
Answer: Option
D
Text Explanation :
From Ganeshan’s statement, there were two candidates in room 102. From Erina’s statement, she was the only candidate in her room.
However, from Balram’s statement, there were at least three candidates in the room 101. Therefore, there were 4 candidates in room 101, 2 candidates in room 102 and 1 candidate in room 103.
Using the given statements, we can generate the following:
Erina reached the venue at 7:45 am
Hence, option (c).
89. CAT 2018 LRDI Slot 2 | LR - Selection & Distribution CAT Question
If Ganeshan entered the venue before Divya, when did Balaram enter the venue?
- (a)
7:10 am
- (b)
7:15 am
- (c)
7:25 am
- (d)
7:45 am
Answer: Option
C
Text Explanation :
From Ganeshan’s statement, there were two candidates in room 102. From Erina’s statement, she was the only candidate in her room.
However, from Balram’s statement, there were at least three candidates in the room 101. Therefore, there were 4 candidates in room 101, 2 candidates in room 102 and 1 candidate in room 103.
Using the given statements, we can generate the following:
If Ganeshan entered before Divya, Balaram entered at 7.25 am.
Hence, option (c).
Answer the following question based on the information given below.
Healthy Bites is a fast food joint serving three items: burgers, fries and ice cream. It has two employees Anish and Bani who prepare the items ordered by the clients. Preparation time is 10 minutes for a burger and 2 minutes for an order of ice cream. An employee can prepare only one of these items at a time. The fries are prepared in an automatic fryer which can prepare up to 3 portions of fries at a time, and takes 5 minutes irrespective of the number of portions. The fryer does not need an employee to constantly attend to it, and we can ignore the time taken by an employee to start and stop the fryer; thus an employee can be engaged in preparing other items while the frying is on. However fries cannot be prepared in anticipation of future orders.
Healthy Bites wishes to serve the order as early as possible. The individual items in any order are served as and when ready; however, the order is considered to be completely served only when all the items of that order are served.
The table below gives the orders of three clients and the times at which they placed their orders:
90. CAT 2017 LRDI Slot 1 | LR - Selection & Distribution CAT Question
Assume that only one client’s order can be processed at any given point of time. So, Anish or Bani cannot start preparing a new order while a pervious order is being prepared. At what time is the order placed by Client 1 completely served?
- (a)
10 : 17
- (b)
10 : 10
- (c)
10 : 15
- (d)
10 : 20
Answer: Option
B
Text Explanation :
Now since only one client's order can be processed at any given point of time, the burger preparation for the first client which takes 10 minutes, will get completed by 10 : 10 by one of the 2 employees.
In the meantime, the 1 order of ice-cream will be completed by the 2nd employee in 2 minutes and will be completed by 10 : 02.
One of the 2 employees can put the 3 portions of french fries in the fryer at 10 and will be completed by 10 : 05.
[He can put the fries in fryer and immediately start with either burger or ice-cream]
As can be seen, out of all 3 items, the burger will be the last item to be prepared for the first client and the preparation of that item will be completed by 10 : 10 am.
So the order of the first client will be completed by 10 : 10.
Hence, option (b).
91. CAT 2017 LRDI Slot 1 | LR - Selection & Distribution CAT Question
Assume that only one client’s order can be processed at any given point of time. So, Anish or Bani cannot start preparing a new order while a pervious order is being prepared. At what time is the order placed by Client 3 completely served?
- (a)
10 : 35
- (b)
10 : 22
- (c)
10 : 25
- (d)
10 : 17
Answer: Option
C
Text Explanation :
As per the answer to the previous question order of client 1 will be completed by 10.10.
For 2nd client:
Since order of only one client can be processed at a time, the 2 portions of fries can be prepared by 10:15 and 1 order of ice-cream by 10:12.
So the order of client 2 will be complete by 10:15.
For 3rd client:
Now, the burger preparation of client 3 can be completed by 10:25 and the preparation of fries can be completed by 10:20.
So, client 3 will be completely served by 10:25.
Hence, option (c).
92. CAT 2017 LRDI Slot 1 | LR - Selection & Distribution CAT Question
Suppose the employees are allowed to process multiple order at a time, but the preference would be to finish orders of clients who placed their orders earlier. At what time is the order placed by Client 2 completely served?
- (a)
10 : 10
- (b)
10 : 12
- (c)
10 : 15
- (d)
10 : 17
Answer: Option
A
Text Explanation :
Suppose Anish will complete preparation of the burger of client 1 by 10:10. In the meantime, Bani will complete the order of ice-cream of client 1 by 10:02. 3 portions of fries would have been prepared by 10:05.
At 10:05 when 2nd client's order comes, Bani would be free and the fryer would also be free.
Bani can put the 2 portions of fries in the fryer (completes at 10:10) and start the order of 1 ice-cream of client 2 which will be completed by by 10.07.
So the entire order of client 2 will complete by 10:10.
Hence, option (a).
93. CAT 2017 LRDI Slot 1 | LR - Selection & Distribution CAT Question
Suppose the employees are allowed to process multiple order at a time, but the preference would be to finish orders of clients who placed their orders earlier. Also assume that the fourth client came in only at 10:35. Between 10:00 and 10:30, for how many minutes is exactly one of the employees idle?
- (a)
7
- (b)
10
- (c)
15
- (d)
23
Answer: Option
B
Text Explanation :
Suppose Anish will complete preparation of the burger of client 1 by 10:10. In the meantime, Bani will complete the order of ice-cream of client 1 by 10:02. 3 portions of fries would have been prepared by 10:05.
Bani would be free from 10:02 till 10:05 i.e., for 3 minutes.
At 10:05 when 2nd client's order comes, Bani and fryper would be free but Anish would be occupied.
Bani can put the 2 portions of fries in the fryer (completes at 10:10) and start the order of 1 ice-cream of client 2 which will be completed by by 10.07. So the entire order of client 2 will complete by 10:10.
At 10:07 when 3rd client's order comes, Bani would be free but fryer and Anish would be occupied.
Bani would start the order of burger and complete it by 10:17.
Anish and fryer both would be free at 10:10 and hence Anish can start the order of 1 portion of fries which would complete by 10:15.
Bani would be free from 10:17 till 10:30.
Anish would be free from 10:10 till 10:30.
Between 10:10 and 10:30 exactly one employee would be free only between 10:10 and 10:17 i.e., for 7 minutes.
Therefore exactly one employee if idle between 10:02 - 10:05 and 10:10 - 10:17 i.e., total 10 minutes.
Hence, option (b).
Answer the following question based on the information given below.
There are 21 employees working in a division, out of whom 10 are special-skilled employees (SE) and the remaining are regular-skilled employees (RE). During the next five months, the division has to complete five projects every month. Out of the 25 projects, 5 projects are “challenging”’ while the remaining ones are “standard”. Each of the challenging projects has to be completed in different months. Every month, five teams – T1, T2, T3, T4 and T5, work on one project each. T1, T2, T3, T4 and T5 are allotted the challenging project in the first, second, third, fourth and fifth month, respectively. The team assigned the challenging project has one more employee than the rest.
In the first month, T1 has one more SE than T2, T2 has one more SE than T3, T3 has one more SE than T4, and T4 has one more SE than T5. Between two successive months, the composition of the teams changes as follows:
a. The team allotted the challenging project, gets two SE from the team which was allotted the challenging project in the previous month. In exchange, one RE is shifted from the former team to the latter team.
b. After the above exchange, if T1 has any SE and T5 has any RE, then one SE is shifted from T1 to T5, and one RE is shifted fromT5 to T1. Also, if T2 has any SE and T4 has any RE, then one SE is shifted from T2 to T4, and one RE is shifted from T4 to T2.
Each standard project has a total of 100 credit points, while each challenging project has 200 credit points. The credit points are equally shared between the employees included in that team.
94. CAT 2017 LRDI Slot 1 | LR - Selection & Distribution CAT Question
The number of times in which the composition of team T2 and the number of times in which composition of team T4 remained unchanged in two successive months are:
- (a)
(2, 1)
- (b)
(1, 0)
- (c)
(0, 0)
- (d)
(1, 1)
Answer: Option
B
Text Explanation :
1. Let number of SE’s (special skilled employees) in T5 in the first month be ‘x’. Then number of SE’s in T4, T3, T2 and T1 will be x + 1, x + 2, x + 3 and x + 4 respectively. As per given data, number of SE’s is 10.
∴ x + x + 1 + x + 2 + x + 3 + x + 4 = 10
∴ x = 0
So number of SE’s in T1, T2, T3, T4 and T5 will be 4, 3, 2, 1 and 0 respectively. Now T1, T2, T3, T4 and T5 get the challenging projects in months.
1, 2, 3, 4 and 5 respectively.
Also as total number of employees in the team having the challenging projects in a particular month is 1 more than the other teams the standard projects in the first month, T1 will have a total of 5 employees in the 1st month and hence 1 RE (Regular Skilled Employee). Since the other teams have a total of 4 employees each in the 1st month, the number of RE’s in T2, T3, T4 and T5 will be 1, 2, 3 and 4 respectively in the first month. So in the 1st month break up of employees in each of the teams will be as follows
In the second month, the number of team members following condition (a) will be as follows
Following condition (b) number of employees in month 2 will be
For month 3 following condition (a)
Following condition (b)
For month 4, following condition (a)
his is the final number of SE’s and RE’s in month4 as after following condition (a) as T1 has no SE and T4 has no RE, no further interchange can happen
For month 5, following condition (a)
Following condition (b)
Using this information let us answer the questions.
The composition of T2 remains unchanged only in months 3 and 4 and that of T4 changes every month. So the correct option to choose is (1, 0).
Hence, option (b).
95. CAT 2017 LRDI Slot 1 | LR - Selection & Distribution CAT Question
The number of SE in T1 and T5 for the projects in the third month are, respectively:
- (a)
(0, 2)
- (b)
(0, 3)
- (c)
(1, 2)
- (d)
(1, 3)
Answer: Option
A
Text Explanation :
1. Let number of SE’s (special skilled employees) in T5 in the first month be ‘x’. Then number of SE’s in T4, T3, T2 and T1 will be x + 1, x + 2, x + 3 and x + 4 respectively. As per given data, number of SE’s is 10.
∴ x + x + 1 + x + 2 + x + 3 + x + 4 = 10
∴ x = 0
So number of SE’s in T1, T2, T3, T4 and T5 will be 4, 3, 2, 1 and 0 respectively. Now T1, T2, T3, T4 and T5 get the challenging projects in months.
1, 2, 3, 4 and 5 respectively.
Also as total number of employees in the team having the challenging projects in a particular month is 1 more than the other teams the standard projects in the first month, T1 will have a total of 5 employees in the 1st month and hence 1 RE (Regular Skilled Employee). Since the other teams have a total of 4 employees each in the 1st month, the number of RE’s in T2, T3, T4 and T5 will be 1, 2, 3 and 4 respectively in the first month. So in the 1st month break up of employees in each of the teams will be as follows
In the second month, the number of team members following condition (a) will be as follows
Following condition (b) number of employees in month 2 will be
For month 3 following condition (a)
Following condition (b)
For month 4, following condition (a)
his is the final number of SE’s and RE’s in month4 as after following condition (a) as T1 has no SE and T4 has no RE, no further interchange can happen
For month 5, following condition (a)
Following condition (b)
Using this information let us answer the questions.
The number of SE in T1 and T5 for month 3 is 0 and 2 respectively.
Hence, option (a).
96. CAT 2017 LRDI Slot 1 | LR - Selection & Distribution CAT Question
Which of the following CANNOT be the total credit points earned by any employee from the projects?
- (a)
140
- (b)
150
- (c)
170
- (d)
200
Answer: Option
B
Text Explanation :
1. Let number of SE’s (special skilled employees) in T5 in the first month be ‘x’. Then number of SE’s in T4, T3, T2 and T1 will be x + 1, x + 2, x + 3 and x + 4 respectively. As per given data, number of SE’s is 10.
∴ x + x + 1 + x + 2 + x + 3 + x + 4 = 10
∴ x = 0
So number of SE’s in T1, T2, T3, T4 and T5 will be 4, 3, 2, 1 and 0 respectively. Now T1, T2, T3, T4 and T5 get the challenging projects in months.
1, 2, 3, 4 and 5 respectively.
Also as total number of employees in the team having the challenging projects in a particular month is 1 more than the other teams the standard projects in the first month, T1 will have a total of 5 employees in the 1st month and hence 1 RE (Regular Skilled Employee). Since the other teams have a total of 4 employees each in the 1st month, the number of RE’s in T2, T3, T4 and T5 will be 1, 2, 3 and 4 respectively in the first month. So in the 1st month break up of employees in each of the teams will be as follows
In the second month, the number of team members following condition (a) will be as follows
Following condition (b) number of employees in month 2 will be
For month 3 following condition (a)
Following condition (b)
For month 4, following condition (a)
his is the final number of SE’s and RE’s in month4 as after following condition (a) as T1 has no SE and T4 has no RE, no further interchange can happen
For month 5, following condition (a)
Following condition (b)
Using this information let us answer the questions.
As 200 points are divided equally between 5 team members working on a challenging project and 100 points are divided equally between 4 team members working on a standard Project, each team
member working on a challenging project gets or 40 points and each team member working on a standard project gets or 25 points. Now each member works on exactly 5 projects.
Let us assume that ‘x’ out of these 5 projects are standard projects and the remaining ‘5 – x’ are challenging projects, so total points in terms of x will be 40(50 – x) + 25x
⇒ 200 – 40 + 25x
⇒ 200 – 15x
Putting values of x as 0, 1, 2, 3, 4 and 5, we get total points as 200, 185, 170, 155, 140 and 125. Looking at the options we can see options (1), (3) and (4) are possible.
Option 2 i.e., 150 is not possible.
Hence, option (b).
97. CAT 2017 LRDI Slot 1 | LR - Selection & Distribution CAT Question
One of the employees named Aneek scored 185 points. Which of the following CANNOT be true?
- (a)
Aneek worked only in teams T1, T2, T3, and T4.
- (b)
Aneek worked only in teams T1, T2, T4, and T5.
- (c)
Aneek worked only in teams T2, T3, T4, and T5.
- (d)
Aneek worked only in teams T1, T3, T4, and T5.
Answer: Option
D
Text Explanation :
1. Let number of SE’s (special skilled employees) in T5 in the first month be ‘x’. Then number of SE’s in T4, T3, T2 and T1 will be x + 1, x + 2, x + 3 and x + 4 respectively. As per given data, number of SE’s is 10.
∴ x + x + 1 + x + 2 + x + 3 + x + 4 = 10
∴ x = 0
So number of SE’s in T1, T2, T3, T4 and T5 will be 4, 3, 2, 1 and 0 respectively. Now T1, T2, T3, T4 and T5 get the challenging projects in months.
1, 2, 3, 4 and 5 respectively.
Also as total number of employees in the team having the challenging projects in a particular month is 1 more than the other teams the standard projects in the first month, T1 will have a total of 5 employees in the 1st month and hence 1 RE (Regular Skilled Employee). Since the other teams have a total of 4 employees each in the 1st month, the number of RE’s in T2, T3, T4 and T5 will be 1, 2, 3 and 4 respectively in the first month. So in the 1st month break up of employees in each of the teams will be as follows
In the second month, the number of team members following condition (a) will be as follows
Following condition (b) number of employees in month 2 will be
For month 3 following condition (a)
Following condition (b)
For month 4, following condition (a)
his is the final number of SE’s and RE’s in month4 as after following condition (a) as T1 has no SE and T4 has no RE, no further interchange can happen
For month 5, following condition (a)
Following condition (b)
Using this information let us answer the questions.
To score 185 points Aneek must have worked in 4 challenging projects and 1 standard projects
1] One way Aneek (as an SE) could have worked is by working on challenging projects in T1, T2, T3 and T4 in months 1, 2, 3 and 4 respectively and worked on a standard project in T4 in month 5. This is possible if Aneek was an SE who was moved from T1 to T2 in month 2, T2 to T3 in month 3 and then T3 to T4 in month 4. Subsequently in month 5, he was retained in T4 for the standard project. So option [1] is possible.
2] Another possibility is if Aneek as an SE was moved from T1 to T2 in month 2 to work on a challenging project, then moved from T2 to T4 in month 3 to work on a standard Project, retained in T4 in month 4 to work on a challenging project and then moved from T4 to T5 in month 5 to work on a challenging project. So option [2] is also possible.
3] Aneek could be an SE working on a standard project in T2 in month 1 and subsequently retained in T2 in month 2, and moved to T3, T4 and T5 in months 3, 4 and 5 to work on challenging projects. So this option too is possible.
4] This option is not possible because Aneek could not have worked in T3 without working in T2 prior to that Hence option [4] is ruled out.
Hence, option (d).
Directions for next 4 questions.
Funky Pizzaria was required to supply pizzas to three different parties. The total number of pizzas it had to deliver was 800, 70% of which were to be delivered to party 3 and the rest equally divided between Party 1 and Party 2.
Pizzas could be of Thin Crust (T) or Deep Dish (D) variety and come in either Normal Cheese (NC) or Extra Cheese (EC) versions. Hence, there are four types of pizzas: T-NC, T-EC, D-NC and D-EC. Partial information about proportions of T and NC pizzas ordered by the three parties is given below:
98. CAT 2017 LRDI Slot 2 | LR - Selection & Distribution CAT Question
How many Thin Crust pizzas were to be delivered to Party 3?
- (a)
398
- (b)
162
- (c)
196
- (d)
364
Answer: Option
B
Text Explanation :
Now 70% of the pizzas were delivered to party 3 and the balance 30% of the pizzas were delivered to the remaining 2 parties i.e., Party 1 and Party 2. So each of Party 1 and Party 2 will receive
× 800 = 120 pizzas.
Party 3 will receive × 800
= 560 pizzas.
Now number of Thin crust pizzas received by Party 1 = 0.6 × 120 = 72
So number of Deep dish pizzas received by Party 1 = 120 – 72 = 48
Similarly, number of Thin crust pizzas received by Party 2 = 0.55 × 120 = 66 and number of deep dish pizzas received by party 2 = 120 – 60 = 54
Number of normal cheese pizzas received by party 2 = 0.3 × 120 = 36
Number of extra cheese pizzas received by party 2 = 120 – 36 = 84
Now number of normal cheeze pizzas received by party 3 = 0.65 × 560 = 364
So number of extra cheese pizzas received by party 3 = 560 – 364 = 196
Now total number of Thin crust pizzas delivered to the 3 parties = 0.375 × 800
= 300
So, number of Deep Dish Pizzas delivered to the 3 parties = 800 – 416 = 384
So number of thin crust pizzas received by party B = 300 – (72 + 66) = 162 and number of deep dish pizzas received by party 3 = 500 – (48 + 54) = 398
Let number of thin crust normal cheese pizzas received by party 1, 2 and 3 be a, b and c.
Now number of deep dish normal cheese pizzas received by party 2 = 36 – b
So, the number of deep dish extra cheese pizzas received by party 2 = 54 – (36 – b) = 18 + b
Now total number of extra cheese deep dish pizzas received by party 3 = 196 – (162 – c) = 34 + c
Let number of deep pan normal cheese pizzas received by party 1 be ‘d’.
∴ Number of deep dish extra cheeze pizzas will be ‘48-d’
Now let us represent all this information in a table given below:
As can be seen from the table, number of thin crust pizzas delivered to party 3 is 162.
Hence, option (b).
99. CAT 2017 LRDI Slot 2 | LR - Selection & Distribution CAT Question
How many Normal Cheese pizzas were required to be delivered to Party 1?
- (a)
104
- (b)
84
- (c)
16
- (d)
196
Answer: Option
C
Text Explanation :
Now 70% of the pizzas were delivered to party 3 and the balance 30% of the pizzas were delivered to the remaining 2 parties i.e., Party 1 and Party 2. So each of Party 1 and Party 2 will receive
× 800 = 120 pizzas.
Party 3 will receive × 800
= 560 pizzas.
Now number of Thin crust pizzas received by Party 1 = 0.6 × 120 = 72
So number of Deep dish pizzas received by Party 1 = 120 – 72 = 48
Similarly, number of Thin crust pizzas received by Party 2 = 0.55 × 120 = 66 and number of deep dish pizzas received by party 2 = 120 – 60 = 54
Number of normal cheese pizzas received by party 2 = 0.3 × 120 = 36
Number of extra cheese pizzas received by party 2 = 120 – 36 = 84
Now number of normal cheeze pizzas received by party 3 = 0.65 × 560 = 364
So number of extra cheese pizzas received by party 3 = 560 – 364 = 196
Now total number of Thin crust pizzas delivered to the 3 parties = 0.375 × 800
= 300
So, number of Deep Dish Pizzas delivered to the 3 parties = 800 – 416 = 384
So number of thin crust pizzas received by party B = 300 – (72 + 66) = 162 and number of deep dish pizzas received by party 3 = 500 – (48 + 54) = 398
Let number of thin crust normal cheese pizzas received by party 1, 2 and 3 be a, b and c.
Now number of deep dish normal cheese pizzas received by party 2 = 36 – b
So, the number of deep dish extra cheese pizzas received by party 2 = 54 – (36 – b) = 18 + b
Now total number of extra cheese deep dish pizzas received by party 3 = 196 – (162 – c) = 34 + c
Let number of deep pan normal cheese pizzas received by party 1 be ‘d’.
∴ Number of deep dish extra cheeze pizzas will be ‘48-d’
Now let us represent all this information in a table given below:
Now, number of normal cheese pizzas delivered to all parties is 416. Also total number of normal cheese pizzas delivered to party 1 = a + d
∴ 416 = a + b + c + d + 36 – b + 364 – c
416 = a + d + 400
⇒ a + d = 16.
Hence, option (c).
100. CAT 2017 LRDI Slot 2 | LR - Selection & Distribution CAT Question
For Party 2, if 50% of the Normal Cheese pizzas were of Thin Crust variety, what was the difference between the numbers of T-EC and D-EC pizzas to be delivered to party 2?
- (a)
18
- (b)
12
- (c)
30
- (d)
24
Answer: Option
B
Text Explanation :
Now 70% of the pizzas were delivered to party 3 and the balance 30% of the pizzas were delivered to the remaining 2 parties i.e., Party 1 and Party 2. So each of Party 1 and Party 2 will receive
× 800 = 120 pizzas.
Party 3 will receive ⇒ × 800
= 560 pizzas.
Now number of Thin crust pizzas received by Party 1 = 0.6 × 120 = 72
So number of Deep dish pizzas received by Party 1 = 120 – 72 = 48
Similarly, number of Thin crust pizzas received by Party 2 = 0.55 × 120 = 66 and number of deep dish pizzas received by party 2 = 120 – 60 = 54
Number of normal cheese pizzas received by party 2 = 0.3 × 120 = 36
Number of extra cheese pizzas received by party 2 = 120 – 36 = 84
Now number of normal cheeze pizzas received by party 3 = 0.65 × 560 = 364
So number of extra cheese pizzas received by party 3 = 560 – 364 = 196
Now total number of Thin crust pizzas delivered to the 3 parties = 0.375 × 800
= 300
So, number of Deep Dish Pizzas delivered to the 3 parties = 800 – 416 = 384
So number of thin crust pizzas received by party B = 300 – (72 + 66) = 162 and number of deep dish pizzas received by party 3 = 500 – (48 + 54) = 398
Let number of thin crust normal cheese pizzas received by party 1, 2 and 3 be a, b and c.
Now number of deep dish normal cheese pizzas received by party 2 = 36 – b
So, the number of deep dish extra cheese pizzas received by party 2 = 54 – (36 – b) = 18 + b
Now total number of extra cheese deep dish pizzas received by party 3 = 196 – (162 – c) = 34 + c
Let number of deep pan normal cheese pizzas received by party 1 be ‘d’.
∴ Number of deep dish extra cheeze pizzas will be ‘48-d’
Now let us represent all this information in a table given below:
If 50% of the normal cheese pizzas delivered to party 2 are of thin crust variety, then b : 36 – b
= 1 : 1
= 1 ⇒ 2b = 36 or b = 18
So number if T-EC pizzas = 66 – b = 66 – 18 = 48
Also, number of D-EC pizzas = 18 + b = 18 + 18 = 36
So difference between number of T-EC and D-EC pizzas = 48 – 36 = 12
Hence, option (b).
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