Discussion

Explanation:

P (problem is solved) = P (only A solves) + P (only B solves) + P (only C solves).

∴ P (only A solves) = P (A solves) × P (B doesn’t solve) × P (C doesn’t solves)

∴ P (only A solves) = $\frac{1}{3}\times \frac{3}{4}\times \frac{4}{5}$ = $\frac{1}{5}$

Similarly, P (only B solves) = $\frac{2}{3}\times \frac{1}{4}\times \frac{4}{5}$ = $\frac{2}{15}$

Similarly, P (only C solves) = $\frac{2}{3}\times \frac{3}{4}\times \frac{1}{5}$ = $\frac{1}{10}$

∴ P (problem is solved) = $\frac{1}{5}+\frac{2}{15}+\frac{1}{10}$ = $\frac{6+4+3}{30}$ = $\frac{13}{30}$.

Hence, option (d).

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