If ab=21 and pq=32, then find 2ap-bq3ap+2bq.
Explanation:
Given that a/b = 2/1 and p/q = 3/2
a = 2b and p = 3/2 q
∴ 2ap-bq3ap+2bq = 2×2b×32q-bq3×2b×32q+2bq = 6bq-bq9bq+2bq=5bq11bq = 511
Hence, option (c).
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