Discussion

Question:

If $\frac{a}{b} = \frac{2}{1}$ and $\frac{p}{q} = \frac{3}{2}$ , then find $\frac{2 a p - b q}{3 a p + 2 b q}$ .

Explanation:

Given that a/b = 2/1 and p/q = 3/2

a = 2b and p = 3/2 q

∴ $\frac{2 a p - b q}{3 a p + 2 b q}$ = $\frac{2 \times 2 b \times \frac{3}{2} q - b q}{3 \times 2 b \times \frac{3}{2} q + 2 b q}$ = $\frac{6 b q - b q}{9 b q + 2 b q} = \frac{5 b q}{11 b q}$ = $\frac{5}{11}$

Hence, option (c).

» Your doubt will be displayed only after approval.

Doubts

Feedback