What is the length of the diagonal of a rectangle with an area 48 cm2 and one of its sides as 6 cm?
Explanation:
Opposite sides of a rectangle are equal in length.
∴ AD = BC = 6 cm and AB = CD
Area of a rectangle, A = Length × Breadth
∴ 48 = 6 × CD
∴ CD = 8 cm
∴ AB = CD = 8 cm
A rectangle has all interior angles as right angles i.e. 90°.
In ∆BCD, m∠BAD = 90°
Using Pythagoras theorem, we have,
AB2 + AD2 = BD2
∴ BD2 = 62 + 82
∴ BD = 10 cm
Hence, option (a).
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