Two chords AB and CD of a circle intersect at a point P, which lies outside the circle. If PA = 6 cm, PB = 12 cm and PC = 3 cm, what is the length of CD in cm?
Explanation:
For a circle, if two chords AB and CD intersect at a single point P outside the circle, then,
PA × PB = PC × PD
∴ 6 × 12 = 3 × PD
∴ PD = 24 cm
∴ CD = PD – PC = 24 – 3 = 21 cm.
Hence, option (a).
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