In the given circle with center O, AB and CD are two chords that intersect at point X. DX = 6 cm, CX = 8 cm, and BX = 4 cm. What is the radius of the circle?
Explanation:
If two chords intersect internally as shown in the figure,
DX × CX = AX × BX;
∴ AX = (6 × 8)/4 = 12 cm
AB = AX + BX = 12 + 4 = 16 cm
AB is the diameter of the circle.
∴ Radius AO = 16/2 = 8 cm
Hence, option (c).
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