A can contains a mixture of two liquids A and B is the ratio 5 : 3. When 8 litres of mixture are drawn off and the can is filled with B, the ratio of A and B becomes 5 : 7. How many litres of liquid A was contained by the can initially?
Explanation:
Suppose the can initially contains 15x and 9x of mixtures A and B respectively.
Quantity of A in mixture left = 5x-58×8 = 5x - 5 liters
Quantity of B in mixture left = 3x-38×8 = 3x - 3 liters
∴ 5x-53x-3+8=57
⇒ 35x – 35 = 15x + 25
⇒ x = 3
So, the can contained 15 litres of A.
Hence, option (c).
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