What is the lowest amount of sharpners he could have had on Monday morning?
Explanation:
Now, number of oranges = 50i – sharpeners – erasers = 50i – 15i – 10e = 35i – 10e
In the previous question we had, ⇒ i = 11 + (4 + 3e)/14
When e = 8, i = 13 ⇒ Number of sharpeners = 35 × 13 – 10 × 8 = 375
When e = 22, i = 16 ⇒ Number of sharpeners = 35 × 16 – 10 × 22 = 340
When e = 36, i = 19 ⇒ Number of sharpeners = 35 × 19 – 10 × 36 = 305
i.e., Number of sharpeners decrease by 35 for subsequent values of e and i.
⇒ Number of sharpeners = 305 – 35x
Now, this has to be greater than or equal to 160 as 160 sharpeners are to be sold. ⇒ 305 – 35x ≥ 160 ⇒ x ≤ 145/35 = 4.14
∴ Least number sharpeners on Monday morning = 305 – 35 × 4 = 165.
Hence, 165.
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