Question: There are four sections A, B, C and D in a school. If the percentage of students passing in sections A, B and C is 40%, that of sections A, B, D is 45%, that of A, C, D is 50% and that of B, C, D is 55% then which of the following cannot be the pass percentage of sections A, B, C and D combined together.
Explanation:
Let the number of students in sections A, B, C and D be a, b, c and d respectively.
Let the number of students passing in sections A, B, C and D be p, q, r and w respectively.
Total number of students passing from sections A, B and C = p + q + r = (a + b + c) × 0.4
Total number of students passing from sections A, B and D = p + q + s = (a + b + d) × 0.45
Total number of students passing from sections A, C and D = p + r + s = (a + c + d) × 0.50
Total number of students passing from sections B, C and D = q + r + s = (b + c + d) × 0.55
Adding the 4 equation, we get
3 × (p + q + r + s) = 1.35a + 1.4b + 1.45c + 1.5d
This can be written as:
⇒ 3 × (p + q + r + s) = 1.35(a + b + c + d) + 0.05b + 0.1c + 0.15d
⇒ (p + q + r + s) = 0.45(a + b + c + d) + ( 0 . 05 b + 0 . 1 c + 0 . 15 d ) 3
⇒ ( p + q + r + s ) ( a + b + c + d ) = 0.45 + ( 0 . 05 b + 0 . 1 c + 0 . 15 d ) 3 ( a + b + c + d )
⇒ ( p + q + r + s ) ( a + b + c + d ) × 100 % = 45% + ( 0 . 05 b + 0 . 1 c + 0 . 15 d ) 3 ( a + b + c + d ) × 100 %
⇒ Overall pass percentage is definitely greater than 45%.
This can be also be written as:
⇒ 3 × (p + q + r + s) = 1.5(a + b + c + d) - (0.15a + 0.1b + 0.05c)
⇒ (p + q + r + s) = 0.5(a + b + c + d) - ( 0 . 15 a + 0 . 1 b + 0 . 05 c ) 3
⇒ ( p + q + r + s ) ( a + b + c + d ) = 0.5 - ( 0 . 15 a + 0 . 1 b + 0 . 05 c ) 3 ( a + b + c + d )
⇒ ( p + q + r + s ) ( a + b + c + d ) × 100 % = 50% - ( 0 . 15 a + 0 . 1 b + 0 . 05 c ) 3 ( a + b + c + d ) %
⇒ Overall pass percentage is definitely less than 50%.
∴ Overall pass percentage off all 4 sections combined should be between 45% and 50% (excluding both) .
∴ Overall pass percentage cannot be option (c) 51.3%
Hence, option (c).