Discussion

Explanation:

Let p = 1/x and q = 1/y

5p + 7q = 17         ...(1)

11p + 6q = 28         ...(2)

Now, we have got a system of linear simultaneous equations.

(1) × 11 - (2) × 5 we get,

⇒ 77q – 30q = 187 - 140

⇒ 47q = 47

⇒ q = 1

Substituting value of q in (1) we get p = 2

Now, p = 2 = 1/x ⇒ x = ½

and, q = 1 = 1/y ⇒ y = 1

∴ x + y = 3/2

Hence, option (a).

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