Discussion

Explanation:

Let x = $\sqrt{3\sqrt{3\sqrt{3}\dots .\infty }}$ 

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⇒ x² = 3x 

⇒ x = 0, 3

Since $\sqrt{3\sqrt{3\sqrt{3}\dots .\infty }}$  is a positive number, x can not be 0. Hence, only x = 3 will be accepted.

Hence, option (a).

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