Discussion

Explanation:

Total 24 cards are there with the six friends. Since 6 cards are picked in each round, it means that 4 rounds would have been completed.

⇒ Each friend picks 4 cards (1 in each of the 4 rounds).

Let us rearrange the table based on their seating arrangement.

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If a player draws a heart, he keeps it for himself. Therefore, all the heart cards must have been drawn by the person who has it.

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If a player draws a club, he passes it to the player on his left. Therefore, all the club cards must have been drawn by the person on the right of the one who has it.

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If a player draws a spade, he passes it to the player opposite him. Therefore, all the spade cards must have been drawn by the person opposite to the one who has it.

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If a player draws a diamond, he passes it to the player on his right. Therefore, all the diamond cards must have been drawn by the person on the left of the one who has it.

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Romesh has two 3’s whose suit is unknown. The suit of these 3’s can be either spade or diamonds as club and heart are already present. 3 of spade must have come from Nikhar while 3 of diamond must have come from Akash.

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From (i): Now both the 5 and Q with Achal cannot be clubs since Nikhar cannot draw any more cards. They cannot be heart (already drawn). They both cannot be diamonds as Vishal cannot draw 2 more cards. Hence, they both will be spades which were drawn by Akash.

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The 4 with Sumit cannot be heart and spades (already drawn). It cannot be diamonds since Nikhar cannot draw any more cards. Hence, it has to be clubs which was drawn by Akash.

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Now the 10 with Romesh cannot be hearts (10 of hearts is already present). Hence, it could have been drawn by Vishal or Akash or Nikhar. But Akash and Nikhar cannot draw any more cards, hence it must have been drawn by Vishal and it would have been a club.

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From (ii): There are a total of 5 spades. We already know 6 spades and need one more spade.
Now, Achal has to draw two more cards.

Case 1: Achal draws A and K
For this A has to be diamonds while K should be clubs. This leaves 6 which must be spade, but Achal cannot draw another card now. Hence, this case is rejected.

Case 4: Achal draws 6 and K
For this 6 has to be spades while K should be clubs. This leaves A which must be drawn by Romesh which means A is spades. Now we will have total 8 spades which is not possible. Hence, this case is rejected.

Case 3: Achal draws A and 6
For this A has to be diamonds while 6 should be spades. This leaves K which must be picked by Romesh, hence K should be diamonds. This case is possible.

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∴ Romesh drew both the kings.

Hence, option (b).

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