Discussion

Explanation:

Probability that H is the 1st letter of the code = $\frac{1}{26}$
Probability that I is the 2nd letter of the code = $\frac{1}{26}$
Probability that J is the 3rd letter of the code = $\frac{1}{26}$
Probability that K is the 4th letter of the code = $\frac{1}{26}$

⇒ Required probability = $\frac{1}{26}$× $\frac{1}{26}$ × $\frac{1}{26}$ × $\frac{1}{26}$ = ${\left(\frac{1}{26}\right)}^4$

Hence, option (c).

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