400 tickets are numbered as 000, 001, 002, 003,……., 599. If a ticket is drawn at random from them and M is the event that the sum of the digits of the number is 6, then P(M) =
Explanation:
Total number of tickets = 600
The possible digits and the number of numbers from 000 to 399 only with those digits, are tabulated below.
Possible digits Number of numbers 0 0 6 → 2 0 1 5 → 6 0 2 4 → 6 0 3 3 → 3 1 1 4 → 3 1 2 3 → 6 2 2 2 → 1 Total → 27
∴ Required probability = 27/600 = 9/200
Hence, option (b).
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