If 3 consecutive letters are selected at random from the English alphabet, then the probability that one of the letters is a vowel is:
Explanation:
A B C D E F G H I J K L M N O P Q R S T U V W X Y Z
There are a total of (26 – 2 =) 24 sets of 3 consecutive letters in the alphabet series.
Out these 3 consecutive letters which don’t contain vowels are: B C D F G H J K L K L M L M N P Q R Q R S R S T V W X W X Y X Y Z i.e., total 11 sets. ⇒ Favourable sets = 24 – 11 = 13
∴ Required probability = 13/24.
Hence, option (d).
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