Discussion

Explanation:

Suppose they meet x hrs after 8 a.m. then, (Distance moved by first in x hrs) + [Distance moved bysecond in (x – 1) hrs] = 330

∴60x+75(x-1)=330

⇒x=3

So, they meet at (8 + 3), i.e.11 a.m.

Hence, option (c).

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