A, B and C entered a room and saw a bowl full of apples. Firstly, A ate 5/6th of all the apples and four more apples. Then, B ate 4/5th of the remaining apples and two more apples. Finally, C ate half of the remaining apples and one more apple. To their surprise, one apple was still left in the bowl. Find the difference between the number of apples eaten by A and that eaten by B and C together.
Explanation:
We can solve this question with reverse approach.
Let the number of apples before C ate is x. C ate half of the apples hence number of apples left is x/2. Now, C ate one more apple, hence number of apples left is x/2 – 1 =1 ∴ Number of apples left before C ate = (1 + 1) × 2/1 = 4 C ate half of this + 1 apples i.e., 3 apples.
Similarly, number of apples left before B ate = (4 + 2) × 5/1 = 30 B ate 4/5th of this + 2 apples i.e., 26 apples.
Similarly, number of apples left before A ate = (26 + 4) × 6/1 = 180 A ate 5/6th of this + 4 apples i.e., 154 apples.
Number of apples eaten by A = 154 Number of apples eaten by B and C = 26 + 3 = 29
∴ Required difference = 154 – 29 = 125
Hence, 125.
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