There are three pipes A, B and C which can fill a tank in 6, 5 and 8 hours respectively. All the three pipes were opened simultaneously. It was found that for first 2 hours, pipe A supplied water at 2/5th of its normal capacity, pipe B supplied water at 2/3rd of its normal capacity and pipe C supplied water at 4/5th of its normal capacity. Thereafter, they supplied water at their normal rates. In how much time (in hours) will the tank be full?
Explanation:
Remaining units of work after 2 hrs = 120 – 72 = 48 units
Now, all three pipes work at normal efficiency, hence three pipes together deliver 59 units of work per hour.
∴ Time taken to fining the remaining 48 units = 48/59 hours.
∴ Tank will be full in total of 24859 hrs.
Hence, option (c).
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