Question: Three years ago, the sum of annual incomes of Nikhar and his four brothers A, B, C and D was Rs. 1,20,000. Two years hence, the sum of annual incomes of Nikhar and the two brothers A and D will be Rs. 1,00,000. The present annual incomes, in the given order, of A, B, C and D are in an Arithmetic Progression, with a common difference of Rs. 2,000. If the annual income of Nikhar, along with each of his four brothers, increases by Rs.2,000 every year find the present annual income of Nikhar (in Rs.).
[Enter your answer as the nearest possible integer]
Explanation:
Let us focus on Nikhar and two brothers A and D.
During the five-year interval given in the question, their incomes will grow by 5 × 2000 = Rs. 10,000 each.
If their combined salaries two years hence = Rs. 1,00,000,
⇒ Income of B and C three years ago = 1,20,000 – 70,000 = Rs. 50,000
Now, if B’s income is Rs. x, C’s income will be x + 2000
∴ Income of A = 22,000; B = 24,000; C = 26,000 and D = 28,000
⇒ Present income of Nikhar = 20000 + 6000 = Rs. 26000.
Hence, 26000.