Discussion

Explanation:

Product B:
2018: 80 units of B were produced in 2018.
2019: Since 125 units were in use in 2019, hence (125 – 80 =) 45 units of B were produced in 2019.
Also, 20% of 80 (units produced in 2018) will be discarded at the end of 2019. Hence, number of units left for next year is 125 – 16 = 109
2020: There were 184 units in use during 2020. Hence, number of units produced in 2020 = 184 – 109 = 75.
Also, 10% of 125 (80 + 25 units produced in 2018 & 2019) will be discarded at the end of 2020. Hence, number of units left for next year is 184 – 25 = 159.
2021: There were 229 units in use during 2021. Hence, number of units produced in 2021 = 229 – 159 = 70.

We get the following table for product B.

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Product A:

Since 10% of A produced has to be discarded, hence the number of units of A produced any year will be a multiple of 10.

2016: Let 10x units were produced. (x ≥ 10)
2017: Let 10y units were produced. (y ≥ 10)
2018: Let 10z units were produced. (z ≥ 10)

It is given that at least 100 units of A is produced every year and number of units produced every year is different.
∴ x, y and z are all different.

We can make the following table for product ‘A’ for 2016-2018

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From 2017: Number of units produced 10y = 300 – 10x

⇒ x + y = 30   …(1)

From 2018: Number of units produced = 10z = 390 – (300 - x)
⇒ 10z = 90 + x

Here, the least possible value of x is 10, which gives us z = 10. This is not possible since the number of units produced every year has to be different.

Next possible value of x is 20, which gives z = 11 and y = 10. This is a possible solutions for x, y and z.

For highest values of x, y will not be greater than or equal to 10.

∴ x = 20, y = 10 and z = 11.

Hence, we can complete the table for product ‘A’.

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∴ Number of units of A produced in 2016 = 200.

Hence, option (c).
 

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