Discussion

Explanation:

For a number n = a^x × b^y × c^z

Sum of factors = (a^x + a^x-1 + ... + 1)(b^y + b^y-1 + ... + 1)(c^z + c^z-1 + ... + 1)

360 = 2³ × 3² × 5

Sum of factors of 360 = (2³ + 2² + 2¹ + 1)(3² + 3¹ + 1)(5¹ + 1)

∴ The sum of the factors of 360 = $\left[\frac{\left(2^{\left(3+1\right)}-1\right)\left(3^{\left(2+1\right)}-1\left)\right(5^{(1+1)}-1)\right)}{\left(2-1\right)(3-1)(5-1)}\right]$ = 1170

Hence, 1170.

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