Rohit was 4 times as old as his son 8 years ago. After 8 years, Rohit will be twice as old as his son. What is the sum of their present ages?
Explanation:
Let son's age 8 years ago be x years. ∴ Rohit's age 8 years ago = 4x years.
⇒ Son's age after 8 years = (x + 8) + 8 = (x + 16) years. ⇒ Rohit's age after 8 years = (4x + 8) + 8 = (4x+ 16) years.
⇒ 2(x + 16) = 4x + 16 ⇒ 2x = 16 ⇒ x = 8.
∴ Son's present age = (x + 8) = 16 years. and, Rohit's present age = (4x + 8) = 40 years.
Sum of their present ages = 16 + 40 = 56
Hence, option (c).
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