The ages of two persons differ by 16 years. If 6 years ago, the elder one was 3 times as old as the younger one, find their present ages.
Explanation:
Let the age of the younger person be x years. ∴ Age of the elder person = (x + 16) years.
⇒ 3 (x - 6) = (x + 16 - 6) ⇒ 3x -18 = x + 10 ⇒ 2x = 28 ⇒ x = 14.
∴ Their present ages are 14 years and 30 years.
Hence, option (d).
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