A glass, in the shape of a frustum of a cone is full of water. The radii of the bases of the frustum are 6 cm cm and 4 cm and its height is 14 cm. The glass was emptied into another glass, which is conical with a base radius 4 cm. If the second tank is just full, find its height (in m).
Explanation:
Volume of the frustum of a cone = 1/3 × π × [R2 + Rr + r2] × h
= 1/3 × π × [62 + 6 × 4 + 42] × 14
= 1064/3 cm3.
Let the height of the conical glass be h.
∴ 1/3 × π × r2 × h = 1064/3
⇒ 1/3 × π × 42 × h = 1064/3
⇒ h = 66.5 cm.
Hence, option (d).
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