What is the area (in cm2) of an isosceles triangle ABC with sides AB = AC = 10 cm, and BC = 12 cm?
Explanation:
Since AB = AC, it is an isosceles triangle. The perpendicular drawn from A to BC will bisect side BC.
In right triangle ADB, AB = 10 and BD = 6, hence AD = 8 [6, 8 and 10 is a pythagorean triplet]
∴ Area of triangle = ½ × BC × AD = ½ × 12 × 8 = 48.
Hence, option (b).
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