What is the area (in cm2) of a triangle with sides 6 cm, 8 cm and 10 cm?
Explanation:
s = (a + b + c)/2
where s is the semi-perimeter and a, b and c are the sides of the triangle.
s = (6 + 8 + 10)/2 = 12 cm
Area = ss-as-bs-c
= 1212-612-812-10=12×6×4×2
= 24
Alternately,
6, 8 and 10 are pythagorean triplets i.e. 102 = 82 + 62
⇒ The given triangle is a right triangle
⇒ Area = ½ × 6 × 8 = 24
Hence, option (b).
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