Discussion

Explanation:

S = (x − 1)⁴ + 4(x − 1)³ + 6(x − 1 )² + 4(x − 1) + 1

(a + b)⁴ = ⁴C₀ × a⁴ + ⁴C₁ × a³ × b + ⁴C₂ × a² × b² + ⁴C₃ × a × b³ + ⁴C₄ × b⁴

= a⁴ + 4a³b + 6a²b² + 4ab³ + b⁴

∴ We can see that S = [(x − 1) + 1]⁴ = x⁴

Hence, option (c).

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