Discussion

Explanation:

Construct a line EF parallel to both AB and CD. 

∴ m ∠CEF = m ∠ECD = 20°   (∵ ∠CEF and ∠ECD form a pair of Alternate angles)

Also, m ∠AEG = m ∠EAB = 45°   (∵ ∠AEG and ∠EAB form a pair of Alternate angles)

∴ m ∠GED = 70° − 45° = 25°

But, m ∠GED + m ∠CED + m ∠CEF = 180°

∴ 25° + m ∠CED + 20° = 180°

∴ m ∠CED = 135°

Hence, option (d).

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