Discussion

Explanation:

Given, a2 + b2 + c2 = ab + bc + ca

⇒ 2a2 + 2b2 + 2c2 = 2ab + 2bc + 2ca

⇒ 2a2 + 2b2 + 2c2 - 2ab - 2bc - 2ca = 0

⇒ (a2 - 2ab + b2) + (c2 - 2ac + a2) (b- 2bc + c2) = 0

⇒ (a - b)2 + (a - c)2 + (b - c)2 = 0

This is only possible when a = b = c

∴ The given triangle is an equilateral triangle.

Hence, option (c).

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