What is the distance in cm between two parallel chords of length 16 cm and 12 cm in a circle of radius 10 cm?
Explanation:
We can draw the following diagram from the infomation given.
The perpendicular drawn on a chord from the center of the circle bisects the chord ⇒ BX = 16/2 = 8 and ⇒ DY = 12/2 = 6 and
Now, in ∆BOX ⇒ BO2 = BX2 + OX2 ⇒ 102 = 82 + OX2 ⇒ OX = 6 Also, in ∆BOX ⇒ DO2 = DY2 + OY2 ⇒ 102 = 62 + OY2 ⇒ OY = 8
XY = OX + OY = 6 + 8 = 14
Hence, option (c).
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