Discussion

Explanation:

Square root of 3 - 2√2 will be of the form √x - √y.

∴ (√x - √y)² = 3 - 2√2

⇒ x + y - 2√xy = 3 - 2√2

Now, rational part of RHS = rational part on LHS
⇒ x + y = 3   …(1)

Also, irrational part of RHS = irrational part on LHS
⇒ 2√xy = 2√2
⇒ xy = 2   …(2)

Solving (1) and (2), we get
x = 2 and y = 1 or x = 1 and y = 2.

The square root of 3 - 2√2 will be either √2 - 1 or 1 - √2.

We will reject 1 - √2 as it is negative.

Hence, option (b).

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