Discussion

Explanation:

Using the cyclicity property we calculate the last digit of each term in the above series.

Last digit of 

1¹ = 1
2² = 4
3³ = 7
4⁴ = 6
5⁵ = 5
6⁶ = 6
7⁷ = 3
8⁸ = 6
9⁹ = 9

The sum of all the last digits = 47, which when divided by 5 leaves a remainder of 2.

∴ The remainder when 1¹ + 2² + 3³ + … + 9⁹ is divided by 5 is 2.

Hence, option (c).

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