A group of students is divided into groups of 3, 4 and 5, and each time one student is left out. The least number of students in the heap is
Explanation:
This is a direct application of LCM Model I, as the remainder is the same in all the three cases.
∴ Number of students = LCM(3, 4, 5) + 1 = 60 + 1 = 61
Hence, option (d).
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