Discussion

Explanation:

Let P = Sum borrowed every year

The amount P borrowed at the beginning of 1st year will become at the end P1+101003 of 3rd year.

The amount P borrowed at the beginning of 2nd year will become at the end P1+101002 of 3rd year.

The amount P borrowed at the beginning of 3rd year will become at the end P1+10100 of 3rd year.

Now, P1+101003+P1+101002+P1+10100 = 7282

⇒ P = 2000

Hence, option (a).

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