In a large packet, there are 7 boxes of different weights. If the average (arithmetic mean) weight of these boxes is 'a' pounds, which of the following could be the sum of weights of the 4 heaviest boxes?
Explanation:
As the mean is 'a', the weight of all the boxes should be equal to 7a.
∴ Sum of the 4 heaviest boxes will be less than 7a.
∴ Options (1) and (2) cannot be the answer.
Also, sum of the 4 heaviest boxes has to be greater than the mean of the given 7 numbers, i.e. 3.5a.
∴ Options (4) and (5) cannot be the answer.
Hence, option (c).
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