Discussion

Explanation:

Here we need to insert three arithmetic means between 3 and 23.

Let the AM’s be a, b and c

∴ 3, a, b, c and 23 are in AP.

Let the common different of this AP be ‘d’.

⇒ 23 = 3 + (5 - 1) × d

⇒ d = 5.

First AM = 3 + d = 8
Second AM = 8 + d = 13
Third AM = 13 + d = 18

⇒ AMs are 8, 13, 18.

∴ Sum of the three AMs = 8 + 13 + 18 = 39.

Hence, option (d).

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