What is the area of a regular octagon of side 16 cm?
Explanation:
Area of the octagon = Area of the bigger square – 4 × (Area of the corner right triangle)
The side of the bigger square will be 16 + 16/√2 + 16/√2 = 16 × (1 + √2).
∴ Area of the octagon = (16(1 + √2))2 - 4 × 1/2 × (8√2)2
= 256(3 + 2√2) – 256
= 256(2 + 2√2)
Hence, option (d).
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