In a biased coin, head occurs twice as frequently as tail occurs. If the coin is tossed 3 times, what is the probability of getting two heads?
Explanation:
Given, P(H) = 2 × P(T)
Also, P(H) + P(T) = 1
⇒ 2P(T) + P(T) = 1
∴ P(T) = 1/3 and P(H) = 2/3
Now, P(2 heads out of 3 tosses) = 3C2 × (2/3)2 × (1/3) = 3 × 4/27 = 12/27
Hence, option (b).
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