There are n questions in an exam. A student answered 3 of the first 4 questions correctly. Of the remaining questions he answered one-third correctly. All the questions have the same marks and there is no negative marking. If the student scored 50% marks, how many different values of n can be there?
Explanation:
To score 50% he must have answered 50% questions correctly.
From the conditions of the problem
3 + (n - 4)/3 = 0.5n
⇒ 9 + n – 4 = 1.5n
⇒ 0.5n = 5
⇒ n = 10 (i.e., only one value)
Hence, option (d).
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