Discussion

Explanation:

Given, (abcd)₁₃ – (dcba)₁₃

∴ a × 13³ + b × 13² + c × 13 + d – (d × 13^{​​​​​​​}3 + c × 13² + b × 13 + a) 

= a(13³ - 1) + b (13² - 13) – c(13² - 13) – d(13³ - 1)

Now each of these terms is divisible by 12, hence the number is also divisible by 12.

Hence, option (d).

» Your doubt will be displayed only after approval.