Discussion

Explanation:

When 2 die are rolled total possible outcomes = 6 × 6 = 36

Outcomes for sum to be 2: {(1, 1)} i.e., 1 outcome.
Outcomes for sum to be 12: {(6, 6)} i.e., 1 outcome.

Outcomes for sum to be 3: {(1, 2) or (2, 1)} i.e., 2 outcomes.
Outcomes for sum to be 11: {(6, 5) or (5, 6)} i.e., 2 outcomes.

Outcomes for sum to be 4: {(1, 3) or (3, 1) or (2, 2)} i.e., 3 outcomes.
Outcomes for sum to be 10: {(6, 4) or (4, 6) or (5, 5)} i.e., 3 outcomes.

Similarly, we can draw the following relation between sum and number of outcomes.

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For the sum to exceed 7, desired number of outcomes = 5 + 4 + 3 + 2 + 1 = 15.

∴ Required probability = 15/36 = 5/12.

Hence, option (c).

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