A circular road is constructed outside a square field. The perimeter of the square field is 200 ft. If the width of the road is 7√2 ft. and cost of construction is Rs. 100 per sq. ft. Find the lowest possible cost to construct 50% of the total road.
Explanation:
Radius of inner circle = ½ × diagonal of the square = 25√2 cm Radius of outer circle = Radius of inner circle + width of the road = 32 cm 50% of the area of the road
=12×π×(322)2-(252)2
= 1254 cm2
Cost = 1254 ×100 = Rs. 125,400
Hence, option (b).
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