A man, from the foot of the building P, walks towards the building Q. After walking for 2 mts, he finds that buildings P and Q makean angle of elevation of 60° and 30° respectively. If building Q is 1.5 mts high, find the distance between the tops of both buildings P and Q.
Explanation:
The situation given in the problem can be summarised as:
By 30 - 60 - 90 theorem, we can say that P'M = 4 meters and MQ' = 3 meters Also, triangle P'MQ' would be a right angled triangle. Hence, P'Q' would be the hypotenuse of length = root(16 + 9) = 5 meters
Help us build a Free and Comprehensive Preparation portal for various competitive exams by providing us your valuable feedback about Apti4All and how it can be improved.