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Question:

A cricket team has 11 players and each of them has played 20 matches till date. Virat, Rohit, Mahendra, Rahul and Shikhar have scored runs at an average of 60, 55, 50, 45 and 40 respectively. Rest of the players have scored at an average of 25 each. In the next 10 matches, Virat and Rohit each scored 900 runs whereas Mahendra scored twice that of Rahul. After 30 matches, if Virat’s new average score is twice that of Rahul, what is the approximate average score of Mahendra?

Explanation:

Let Rahul's average after 30 matches be A, so Virat's average after 30 matches is 2A.
 
Virat's score after 30 matches = (60 × 20) + 900 = 2A × 30
 
Solving this equation, we get; A = 35.
 
Rahul's score after 30 matches = (45 × 20) + x = A × 30 = 35 × 30  (where x is the runs scored by Rahul in the last 10 matches)
 
Solving this equation, we get; x = 150.
 
Mahendra's score after 30 matches = (50 × 20) + 2x = B × 30 (where B is the Mahendra's average after 30 matches)
 
Putting x = 150 in the above equation, we get B = 43.33 ≈ 43.
 
Hence option (c).