Please submit your concern

Explanation:

Since there is no condition imposed on x, y and z, assume x = y = z = 10

Consider log_xyz + 1.

When x = y = z = 10; log_xyz + 1

= log₁₀(10 × 10) + 1

= log₁₀(10)² + 1 = 2 log₁₀(10) + 1

= 2(1) + 1 = 3

Similarly, log_yxz + 1 = log_zxy + 1 = 3

∴ Required value = (1/3) + (1/3) + (1/3) = 1

Hence, option (b).