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Explanation:

Let the amount borrowed from each source be Rs. P for n months. 

Since Swarn pays Rs. 62,100 to each firm, it pays the same simple interest to each firm. 

Since it repays the bank 6 months before repayment, its effective loan tenure is (n − 6) months; while for the loan with the microfinance firm, its tenure is n months. 

Considering same interest: [P × 10 × (n − 6)]/(12 × 100) = [P × 8 × n]/(12 × 100)   

∴ 5(n − 6) = 4n i.e. n = 30 

Hence, time period of borrowing = 30 months = 2.5 years. Hence, options 1 and 2 are eliminated. 

Considering the loan with the microfinance firm: 

62100 − P = (P × 8 × 2.5)/100  

∴ 62100 = 1.2P i.e. P = Rs. 51,750

Hence, option (c). 

Alternatively, 

Consider the loan with the microfinance firm. Let the amount borrowed be Rs. P for n years. 

∴ 62100 − P = (P × 8 × n)/100

∴ 62100 = P(1 + 0.08n) 

Now, observe that there are only two values of n (2 and 2.5) in the options). Substitute each value in the above equation and check if the Principal value given in that option is obtained. 

When n = 2; P = 62100/1.16 = Rs. 53,535 (approximately). SInce this value is not in the options, this case is invalid. 

When n = 2.5; P = 62100/1.2 = Rs. 51,750

Hence, option (c).

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