What could be the minimum absolute difference between the scores of FC Pune City and Chennaiyan FC?
Explanation:
Chennaiyan FC have won 5 matches and drawn 2 matches.
∴ Their score = (5 × 3) + (2 × 1) = 17
To minimize the difference of scores between the two team, maximize FC Pune City’s score.
FC City have won 2 matches, lost 2 matches and drawn 1 match. Hence, to maxmiize their score, they should win the reminaing 2 matches. Hence, they should have 4 wins, 2 losses and 1 draw.
∴ Their score = (4 × 3) + (1 × 1) = 13
∴ Minimum absolute difference = 17 – 13 = 4
Hence, option (d).
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