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Explanation:

Number of ways in which the candidate fails to secure the cut-offs in no section out of 6 sections = 6C= 1

Number of ways in which the candidate may/may not secure the cut-offs

6Co6C + 6C + 6C6C6C6C6

= 26 = 64

Thus, the number of ways in which he fails to secure the cut offs in at least one section = 64 − 1 = 63

Hence, option (d).

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