If log255 = a and log2515 = b, then the value of log2527 is:
Explanation:
a + b = log255 + log2515 = log2575 = log2525 + log253
a + b = 1 + log253
a + b – 1 = log253 ∴ log2527 = 3log253 = 3(a + b – 1)
Hence, option (c).
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